Question

7. One end of the steel wire of
area of cross section 3mm2 is
attached to the ceiling of an
elevator moving up with an
acceleration of 2.2m/s2.If a
load of 8 kg is attached at its
free end then the stress
developed in the wire will be
O
8x (10) ^6 N/m^2
0
20x [10] ^6 N/m^2
0
O
32x [10] ^6 N/m^2
16[10] 16 N/m^2​

Answer 1

Answer:

One end of steel wire is fixed ti ceiling of an elevator moving up with an acceleration

amd a load of 10 kg hangs from other end. Area of cross- section of the wire is

.The longitudinal strain in the wire is

.

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Text Solution

Answer :

B

Solution :

(b) As,

<br> Stress

and

<br>

<br>

One end of steel wire is fixed ti ceiling of an elevator moving up with an acceleration

amd a load of 10 kg hangs from other end. Area of cross- section of the wire is

.The longitudinal strain in the wire is

.

like-icon

4.4k LIKES

view-icon

3.4k VIEWS

share-icon

3.4k SHARES

check-circle

Text Solution

Answer :

B

Solution :

(b) As,

<br> Stress

and

<br>

<br>

Answer 2

Answer:

The stress developed in the wire will be 20.8*10⁻⁶N/m².

Explanation:

Given:
Area of wire(A)=3mm²=3*10⁻⁶m

Acceleration(a)=2.2ms⁻²

Mass(m)=8kg

To find: Stress=?
Solution:

Due to the acceleration, tension is developed in the string.

We know that,

$Tension=mg-ma$

=8*(10-2.2)

Tension=62.4N

The stress developed can be calculated using the formula,

$Stress=\frac{Force}{Area}$

=62.4/3*10⁻⁶

=20.8*10⁻⁶N/m²

Therefore, the stress developed in the wire will be 20.8*10⁻⁶N/m².