7. One of the two equal angles of an isosceles triangle
is greater than the third angle by 18°. Find the the
angles of the isosceles triangle.
Answers
Answered by
6
Answer:angles are x,x,x-18
we know that sum of angles of triangle is 180
so x+x+x-18=180
3x=198
x=66
so required angle is x-18 = 66-18= 48
Answered by
10
If one of the two equal angles is greater then the other would also be.
Let the third angle be x and the two equal angles be (x+18)
We know that the sum of a triangle is 180 degrees
X + (x + 18) + (x + 18) = 180
3x + 36 = 180
3x = 180-36
3x = 144
X = 48
Third angle = x = 48 degrees
The two equal angles = x + 18 = 48 + 18 = 66 degrees
Let the third angle be x and the two equal angles be (x+18)
We know that the sum of a triangle is 180 degrees
X + (x + 18) + (x + 18) = 180
3x + 36 = 180
3x = 180-36
3x = 144
X = 48
Third angle = x = 48 degrees
The two equal angles = x + 18 = 48 + 18 = 66 degrees
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