Question

7 power 2 n+1divided by 49=7power 3

Answer 1

Answer:

${7}^{(2n + 1)} \div 49 = \frac{7}{3} \\ \frac{ {7}^{2n + 1} }{49} = {7}^{3} \\ \frac{ {7}^{2n + 1} }{ {7}^{2} } = {7}^{3} \\ {7}^{2n + 1} = {7}^{3} \times {7}^{2} \\ {7}^{2n + 1} = {7}^{(3 + 2)} \\ {7}^{2n + 1} = {7}^{5} \\ 2n + 1 = 5 \\ 2n = 5 - 1 \\ 2n = 4 \\ n = \frac{4}{2} \\ \large{ \boxed{n = \underline{ \underline{ 2}}}} \\ \\ \large{ \underline{Note} : } \\ * \: \: \: \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} \\ * \: \: \: {a}^{m} \times {a}^{n} = {a}^{m + n}$