Question

7. Prove that:<br />(i) tan 20° tan 35° tan 45º tan 55° tan 70° = 1<br />(ii) sin 48° sec 42° + cos 48° cosec 42° = 2<br />sin 70°<br />(üi)<br />-<br />cosec 20°<br />+<br />cOS 20°<br />sec 70°<br />- 2 cos 70° cosec 20º = 0<br />(iv) COS 80<br />°<br />+ cos 59° cosec 31° = 2<br />sin 10°​
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Answer 1

Answer:

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Step-by-step explanation:

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