7
Q.4. Solve any Four questions -
14 +[{-10X (25 – 13 – 3)} = (-5)]
A.
Answers
Answer:
14+\frac{1}{5}\left[\left\{-10\times \left(25-12-3\right)\right\}\right]\div \left(-5\right)=\frac{88}{5}14+
5
1
[{−10×(25−12−3)}]÷(−5)=
5
88
Step-by-step explanation:
Given : 14+\frac{1}{5}\left[\left\{-10\times \left(25-13-3\right)\right\}\right]\div \left(-5\right)14+
5
1
[{−10×(25−13−3)}]÷(−5)
We will solve using BODMAS
B denotes bracket
O denotes Order
D denotes division
M denotes multiplication
A denotes addition
S denotes Subtraction
Step-by-step explanation:
Given : 14+\frac{1}{5}\left[\left\{-10\times \left(25-13-3\right)\right\}\right]\div \left(-5\right)14+
5
1
[{−10×(25−13−3)}]÷(−5)
We will solve using BODMAS
=14+\frac{1}{5}\times \frac{-10\left(25-13-3\right)}{-5}=14+
5
1
×
−5
−10(25−13−3)
Solving brackets, we get,
=14+(\frac{1}{5}\times \frac{-10\left(25-16\right)}{-5})=14+(
5
1
×
−5
−10(25−16)
)
=14+(\frac{1}{5}\times \frac{10 \times 9}{5})=14+(
5
1
×
5
10×9
)
=14+(\frac{1}{5}\times 18 }
=14+\frac{18}{5}=14+
18
=\frac{88}{5}=
5
88