Math, asked by vaishnavi0050, 10 hours ago

7. Rationalise the denominator
ii- √2/√2+√3-√5​

Answers

Answered by adityadarvesh143
0

Answer:

Now Multiply Numerator and Denominator.

\begin{gathered} \frac{1( \sqrt{3 + } \sqrt{2} ) + \sqrt{5} }{[( \sqrt{3} + \sqrt{2} ) - \sqrt{5}]\:[ ( \sqrt{3} + \sqrt{2}) + \sqrt{5} ]} \\ \\ \frac{( \sqrt{3} + \sqrt{2} ) + \sqrt{5} }{( \sqrt{3} + \sqrt{2} ) {}^{2} - \sqrt{5} {}^{2} } \\ \\ \frac{ \sqrt{3} + \sqrt{2} + \sqrt{5} }{3 + 2 + 2 \sqrt{3 \times 2} - 5} \\ \\ \frac{ \sqrt{3} +\sqrt{2}+ \sqrt{5} }{5 + 2 \sqrt{6} - 5 } \\ \\ \frac{ \sqrt{3} + \sqrt{2} +\sqrt{5} }{2 \sqrt{6} } \end{gathered}

[(

3

+

2

)−

5

][(

3

+

2

)+

5

]

1(

3+

2

)+

5

(

3

+

2

)

2

5

2

(

3

+

2

)+

5

3+2+2

3×2

−5

3

+

2

+

5

5+2

6

−5

3

+

2

+

5

2

6

3

+

2

+

5

Answered by purshutamyadav90
0
Hope you understand
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