Question

7. Reeta has 8 chocolates more than Seema. If they have 40 chocolates in
total, find the chocolates both with Reeta and Seema.

Answer 1

Answer:

chocolates of reeta + seema =40

: (x+8) + x =40

: 2x+8 =40

: 2x =40-8

: 2x. =32

: x. =16

therefore,

reeta chocolates= x+8

= 16+8

=24

Seema chocolates=x=16

please mark it as brainlist

Answer 2

IT is your Please Mark as brainlist and thanks