Question

7. Replace * by the smallest digit so that the number formed is divisible by 9.
(a) 6*5
(b) 21*2.
Ilsing the digits 1 and 5 form the smallest three-digit number which are divisible by ea​

Answer 1

Step-by-step explanation:

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Answer 2

(a)

The number is given as _6724.

The number is divisible by 3 if the sum of its digits is divisible by 3.

Adding the digits of the given number,

6+7+2+4=19

If 2 is added to the above number then the number will become 21 which is divisible by 3 and also, 2 is the smallest number that can fill the missing space.

Now, if 8 is added to the given number then the number will become 27 which is divisible by 3 and 8 is largest number that can make the given number divisible by 3.

Therefore, the smallest number will be 2 which will form 26724 and the largest number will be 8 forming 86724.

(b)

The number is given as 4765_2.

The number is divisible by 3 if the sum of its digits is divisible by 3.

Adding the digits of the given number,

4+7+6+5+2=24

If 0 is added to the above number then the number will become 24 which is divisible by 3 and also, 0 is the smallest number that can fill the missing space.

Now, if 9 is added to the given number then the number will become 33 which is divisible by 3 and 9 is largest number that can make the given number divisible by 3.

Therefore, the smallest number will be 0 which will form 476502 and the largest number will be 9 forming 476592.

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