7. Ruben examines up to a tank of water that can hold up to 10 gallons. When it is
active, a drain empties water from the tank at a constant rate. When Ruben first sees
the tank, it contains 9 gallons of water, four minutes later, the tank contains 6 gallons of water.
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Answer :-
given that,
→ When Ruben first sees the tank, it contains water = 9 gallons .
→ 4 minutes later, the tank contains water = 6 gallons.
so,
→ in 4 minutes water empty = 9 - 6 = 3 gallons .
then,
→ Rate of changing the water = (3/4) gallons / minutes .
since water is decreasing per minutes , the rate will be in negative .
now,
→ water tanks was completely full before = 10 gallons = before 9 gallons = 1 gallon = 1/(3/4) = (4/3) minutes .
also,
→ Time taken by tank to drain completely = 6 / (3/4) = 6 * (4/3) = 8 more minutes .
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