Question

7 sec^2A - 7 tan^A - 5 is equal to


please help me fast.
please don't post irrelevant answer ​

Answer 1

Answer is given in the pic.

Answer 2

$\begin{gathered}\large {\boxed{\sf{\mid{\overline {\underline {\star ANSWER ::}}}\mid}}}\end{gathered}$

To Find :-

$➪ \: 7 \sec {}^{2} a - 7 \tan {}^{2} a - 5$

Solution :-

$\: 7 \sec {}^{2} a - 7 \tan {}^{2} a - 5 \\ = 7( \sec {}^{2} a - \tan {}^{2} a) - 5 \\ = 7(1) - 5 \\ \large \boxed{= 2}$

IDENTITY USED :

$\large \boxed{ \bold { \star \: \sec {}^{2}a - \tan {}^{2} a = 1 }}$

@SweetestBitter