Question

7
(sec theta+ cos theta) (sec theta
(sec theta - cos theta) = tan2 theta + sin 2 theta​

Answer 1

Step-by-step explanation:

L.H.S= (secA + cosA)(secA-cosA)

= sec²A - cos²A

= 1 + tan²A - ( 1- sin²A)

= 1 + tan²A - 1 + sin²A

= tan²A + sin²A

= R.H.S

Here I have written A instead 'theta'

I hope this will help you.

Thank you.

Happy to help.