Question

7. Show that if a body is taken to a height H above
earth's surface, acceleration due to gravity
decreased by the factor RP/(R + H)2, where R is
radius of the ea5​

Answer 1

Answer:

It is ok

Explanation:

let we consider,

radius of earth R and mass is M

and we know that acceleration due to gravity at surface

g=

R

2

GM

---- (i)

G is universal gravitational constant.

consider, a mass m is at above the earth at height h and g

′

is acceleration due to gravity at height h.

Therefore, g′=

(R+h)

2

GM

----- (ii)

divide, (ii) by (i)

g

g

′

=

(R+h)

2

R

2

g

′

=

(R+h)

2

gR

2

For h<<<R,

g

′

=g(1−

R

2h

)