Question

7. Shyam traveled three distances of 220
km, 182 km, 192 km in
three days. Each day, he spent 2 hr for
journey. What is net
speed of Shyam in km/hr?
110
99
96
91​

Answer 1

Anser:-

= 2 hours.

Therefore,

192/x - 192/(x + 16) = 2   Taking L.C.M.. we get

192x + 3072 + 192x   

_______________   = 2

 x (x + 16)

3072/x(x + 16) = 2    After cross multiplying, we get

3072 = 2x² + 32x

2x² + 32x - 3072 = 0

Dividing it by 2, we get

x² + 16x - 1536 = 0 

x² + 48x - 32x - 1536 = 0

x(x + 48) - 32(x + 48) = 0

(x + 48) (x - 32) = 0

x = - 48 or x = 32

The speed of the train cannot be negative, therefore the speed of the passenger train is 32 km/hr

And the speed of the super fast train is 32 + 16 = 48 km/hr