7 sin^2 A + 3 cos^2 A = 4.When A is an acute angle, Show that cot A = √3
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Answer:
sin^2A=1-cos^2A
then
7-7cos^A+3cos^2A =4
7-4cos^A=4
4cos^A=3
cos^a=3/4
A=30
then
cot30=√3
hence proved
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