7 sin square theta + 3 cos square theta = 4 , show that tan theta = 1/3
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=(7 sin2 theta +3cos2 theta)/cos2 theta=4/cos2 theta
=7 tan2 theta + 3 = 4/cos2 theta
=7tan2 theta - 4 sec2 theta + 3 =0
=7tan2 theta -4(1+tan2 theta) + 3=0
=7tan2 theta -4 -4tan2 theta + 3=0
= 3tan2 theta -1 = 0
= 3tan2 theta=1
= tan2 theta =1/3
= tan theta= 1/ root over 3
hence,proved.
ratishrajanmolraj:
Only prove 1/3
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