7 sin square theta + 3 cos square theta equal to 4
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Answered by
1
Answer:
7sin^2a+3cos^2a=4. here a= theta
7(1-cos^2a)+3cos^2a=4
7-7cos^2a+3cos^2 a=4
7-4cos^2 a = 4
cos a=+/- √3/2
Answered by
2
Step-by-step explanation:
7sin^2 theta+3 cos^2 theta=4
=>7sin^2 theta+3(1-sin^2 theta)=4
=>7sin^2theta+3-3sin^2theta=4
=>4sin^2theta=4-3=1
=>sin^2theta=1/4
=>sin theta=1/2=sin30
=>theta=30
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