Question

7 sin²theeta + 3cos²theeta = 4
show tan theeta = 1/√3​

Answer 1

Step-by-step explanation:

hope it helps you friend!

Answer 2

7sin²θ + 3cos²θ = 4

• dividing the equation by cos²θ , we get,

7tan²θ + 3 = 4sec²θ

• writing (1+tan²θ) in place of sec²θ,

7tan²θ + 3 = 4(1+tan²θ)

$\implies$ 7tan²θ + 3 = 4 + 4tan²θ

$\implies$ 7tan²θ -4tan²θ = 4-3

$\implies$ 3tan²θ = 1

$\implies$ tan²θ = 1/3

$\implies$ tanθ = 1/√3