Question

7) solve the following by substitution method :-
i) 2x + 3y =s , 3x + 4y = 6​

Answer 1

2x+3y=9 ……. (1)

3x+4y=5 …… (2)

Now,

y=

3

9−2x

On putting the value of y, in equation (2), we get

3x+4(

3

9−2x

)=5

3x+

3

36−8x

=5

9x+36−8x=15

x=15−36

Now, put the value of x in equation (1), we get

y=

3

9−2(−21)

y=

3

9+42

y=

3

51

=17

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Answer 2

Answer:

2x+3y=s

2(1)+3(1)=s

s=2+3

s=5

3x+4y=6

3(2)+4(0)=6

1. 6+0=6