Question

7. Solve, using formula :
x^2 + x - (a + 2) (a + 1) = 0​

Answer 1

Answer :

Roots of given equation are : (a+1) and -(a+2

Explanation :

x² + x - (a+2)(a+1) = 0

Comparing it with, ax² + bx + c = 0, we get,

• a = 1
• b = -1
• c = -(a+2)(a+1)

Quadratic formula :

x = (-b±√D)/2a

=> x = [-1±√(1²-4(-a+2)(a+1)]/(2×1)

=> x = [-1±√{1-4(-a²+3a+2)}]/2

=> x = [-1±√(4a²+12a+9)]/2

=> x = [-1±(2a+3)]/2

=> x = (2a+2)/2 and x = (-2a-4)/2

=> x = a + 1x => -(a+2)

.°. Roots of given equation are : (a+1) and -(a+2)

Answer 2

QUESTION:-

Solve, using formula :

x^2 + x - (a + 2) (a + 1) = 0 .

SOLUTION:-

➠ Given, x²+x-(a+2)(a+1) = 0

➠ Comparing with ax²+bx+c = 0 , then we get

➠ ● a = 1 , ● b = -1 & ● c = -(a+2)(a+1)

➠ use Quadratic formula,

➠ x = (-b ±√D) /2a

Now,

➠ x = [-1±√(1²-4(-a +2)(a +1)]/(2×1)

➠ x = [ -1 ± √(1 -4 ( - a² +3a +2)] / 2

➠ x = [ -1 ± √(4a² +12a +9)]/2

➠ x = [ -1 ± (2a +3)]/2

➠ x = (2a +2)/2 & x =( -2a -4)/2

➠ .°. x = a +1x ➠ x = -(a +2)

So, Roots of given equation are :- (a +1) & -(a+2).

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Q. what is quadratic function formula?

ans :- the quadratic formula is simply just ax²+bx+c = 0 in terms of x. So the roots of ax²+bx+c = 0 would just be the quadratic equation, which is: (-b+-√b²-4ac) / 2a.

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