Question

7. Subtract the sum of 4x2y – 3xy2 + 4 and – 3xy – 7xy2 – 7 from x2 + 4.​

Answer 1

Answer:

Step-by-step explanation:

(y^3+2*2-3xy^2+3xy) -(x^3-2xy^2+4x^2y) =(y^3-x^3)+(-3xy^2+2xy^2) +(3xy-4x^y+4)

=y^3-x^3-xy^2+3xy-4x^2y+4

Answer 2

$({x}^{2} + 4) - ( {4x}^{2} y - 3x {y}^{2} + 4) + ( - 3xy - 7x {y}^{2} - 7) \\ {x }^{2} + 4 - {4x}^{2} y + 3x {y}^{2} - 4 - 3xy - 7x {y}^{2} - 7 \\ {x}^{2} - 4 {x}^{2} y + 3x {y}^{2} - 7x {y}^{2} - 3xy - 7.$

hopefully its helped u dear :)