Question

7 .) Susan bought a bangle weighting 7.4 a necklace weighing 10.8 grams . She bought a ring also and the total weight of all three is 20 grams. what is the weight of the ring

Answer 1

1.8 grams

Step-by-step explanation:

20.0-(7.4+10.8)

=20.0-18.2

= 1.8 grams

Answer 2

As per the details provided in the question we have,

The given data is,

The weight of a bangle is WB=7.4grams

The weight of a necklace is WN=10.8grams

The total weight of all 3 ornaments is TW=20grams

We have to find the weight of the ring i.e. TR.

Thus, the weight of the ring is as follow,

Total weight is equal to the weight of the bangle plus the weight of the necklace plus the weight of the ring.

$TW=TB+TN+TR$

$20=7.4+10.8+TR\\TR=20-7.4-10.8\\TR=1.8grams$

Hence the weight of the ring is 1.8grams

Note:-Susan bought a bangle weighting 7.4grams a necklace weighing 10.8 grams . She bought a ring also and the total weight of all three is 20 grams. what is the weight of the ring