Question

7. Swamy is 25 years older than his son. His age will
be twice the age of his son after 2 years. What is the
present age of the son?​

Answer 1

Step-by-step explanation:

Let the age of the son be X.

Swami's age=25+x

Swamis age after 2 year= 25+x+2.

Son age after 2 years = x+2

Given, swamis age is equal to twice the age of his son after 2 years.

So, 25+x+2= 2(x+2)

= 25+x+2= 2x +4

= 27+x= 2x +4

= x-2x=4-27

=-1x= -23

=x=23