7 th question plz answer
Attachments:
Answers
Answered by
1
There are 1 to 12 classes of 3 sections and so 1st class will plant 1 plant in each section which results in 3 plants in first class similar to so on and it results in an A.P series (3,6,9,14,15,.........36)
So An=n÷2(2a+(n-1)d). .... A=3 d=3 n=12 so 6×((6+(11×3))=
39×6=234trees in total
So An=n÷2(2a+(n-1)d). .... A=3 d=3 n=12 so 6×((6+(11×3))=
39×6=234trees in total
Similar questions