Question

7. The 2nd term of a G.P is 27 and 7 term is 1/9

Find 'a' and 'r​

Answer 1

Answer:

Let The series be a,ar,ar

2

⋯

⟹ar

3

=27⋯(1)

⟹ar

6

=729⋯(2)

(2)÷(1)

ar

3

ar

6

=

27

729

r

3

=27

⟹r=

3

27

r=3

⟹a=1

So the 5th term of G.P. ⟹ar

4

=1×3

4

=81