7. The adjacent sides of a rectangle are -6x2 + 7x2 y2 + xy and 7xy -- 5x + 9x+y. Find its perimeter.
8. The perimeter of a triangle is 7x2 - 17xy + 15y2 + 8 and two sides are 3x2 - 6xy + 4y? -- 5 and
2x2 – 9xy + 6y2 + 6. Find the third side of the triangle.
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Answer:
7)The perimeter of rectangle =2(10x^{2} -5y^{2}-xy)=2(10x
2
−5y
2
−xy) or 20x^{2} -10y^{2}-2xy20x
2
−10y
2
−2xy .
Step-by-step explanation:
We have,
The two adjacent sides of a rectangle = 3x^{2} -5y^{2}3x
2
−5y
2
and 7x^{2} -xy7x
2
−xy
Here, length(l) =3x^{2} -5y^{2}=3x
2
−5y
2
and breadth(b) =7x^{2} -xy=7x
2
−xy
To find, the perimeter of rectangle = ?
We know that,
The perimeter of rectangle =2(Length + Breadth)
=2(3x^{2} -5y^{2}+7x^{2} -xy)=2(3x
2
−5y
2
+7x
2
−xy)
=2(10x^{2} -5y^{2}-xy)=2(10x
2
−5y
2
−xy)
=20x^{2} -10y^{2}-2xy=20x
2
−10y
2
−2xy
Hence, the perimeter of rectangle=2(10x^{2} -5y^{2}-xy)=2(10x
2
−5y
2
−xy) or 20x^{2} -10y^{2}-2xy20x
2
−10y
2
−2xy
8)IDK
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