Math, asked by sanjaykumar3004, 9 months ago

7. The adjacent sides of a rectangle are -6x2 + 7x2 y2 + xy and 7xy -- 5x + 9x+y. Find its perimeter.
8. The perimeter of a triangle is 7x2 - 17xy + 15y2 + 8 and two sides are 3x2 - 6xy + 4y? -- 5 and
2x2 – 9xy + 6y2 + 6. Find the third side of the triangle.​

Answers

Answered by vasudhagrawal
0

Answer:

7)The perimeter of rectangle =2(10x^{2} -5y^{2}-xy)=2(10x

2

−5y

2

−xy) or 20x^{2} -10y^{2}-2xy20x

2

−10y

2

−2xy .

Step-by-step explanation:

We have,

The two adjacent sides of a rectangle = 3x^{2} -5y^{2}3x

2

−5y

2

and 7x^{2} -xy7x

2

−xy

Here, length(l) =3x^{2} -5y^{2}=3x

2

−5y

2

and breadth(b) =7x^{2} -xy=7x

2

−xy

To find, the perimeter of rectangle = ?

We know that,

The perimeter of rectangle =2(Length + Breadth)

=2(3x^{2} -5y^{2}+7x^{2} -xy)=2(3x

2

−5y

2

+7x

2

−xy)

=2(10x^{2} -5y^{2}-xy)=2(10x

2

−5y

2

−xy)

=20x^{2} -10y^{2}-2xy=20x

2

−10y

2

−2xy

Hence, the perimeter of rectangle=2(10x^{2} -5y^{2}-xy)=2(10x

2

−5y

2

−xy) or 20x^{2} -10y^{2}-2xy20x

2

−10y

2

−2xy

8)IDK

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