7. The age of the father 4 years ago was 8 times the age of his son. At present the fall
age is 4 times that of his son. What are the present ages of the father and the
(a) S-7, F-28
(b) S-8, F-32 (c) S-6, F-24
(d) None of these
Answers
Step-by-step explanation:
At present father age is 4 times the age of the son age let x be the age of the father = 4s=x
so the age of the son is 6 4×6= 24
so the answer is C
Answer ❤️
a) S-7 , F-28.
The son is 7 years old.
The problem can be represented by a system of equations. Where 1 equation represent the relationship between their current age and how old they were 4 years ago and one represent the current relationship of their ages.
F = Father's current age.
S = Son's Current age.
So 4 years ago
1. F-4 = 8 ( S -4)
2. F = 4S
the first equation is the more tricky one and people will usually leave out the - 4 for the son.
The second equation is already solved for the F variable so take that expression that is equivalent to F ( 4S ) and plug it into the first equation. Now you Will have a one variable for the sons current age.
4S -4 = 8 (S-4)
4S-4 = 8S - 32
Add 32 and subtract 4s from both sides.
28 = 4S
S = 7
The sons current age is 7, his father is currently 28, and four years ago the son would have been 3 and his father 24.