Hindi, asked by itzadi040, 6 months ago

7. The amount of solute (molar mass 60 g mol-1)
that must be added to 180 g of water so that the
vapour pressure of water is lowered by 10% is​

Answers

Answered by tanyarawat71
2

Answer:

30 g

60 g

120 g

12 g

Answer : 

B

Solution : 

Relative lowering of vapour pressure is given by the formula : 

p∘−psp∘=ωAmA×mBωBp∘-psp∘=ωAmA×mBωB 

Given, relative lowering of vapour pressure 

=p∘−psp∘=10100=p∘-psp∘=10100 

mA=60,mB=18,ωB=180,ωA=xmA=60,mB=18,ωB=180,ωA=x 

∴10100=x/60180/18⇒110=x/6010⇒x=60∴10100=x/60180/18⇒110=x/6010⇒x=60 

Thus, 60 g of the solute must be added to 180 g of water so that the vapour pressure of water is lowered by 10%.

Explanation:

hope u like

Answered by llPrettyStrangerll
1

Answer:

A mitochondrion is a double-membrane-bound organelle found in most eukaryotic organisms. Mitochondria use aerobic respiration to generate most of the cell's supply of adenosine triphosphate, which is subsequently used throughout the cell as a source of chemical energy.

Explanation:

Fb : Shinae H

Attachments:
Similar questions