Math, asked by hacker79, 10 months ago

7. The area of a rectangular field is 3400 m2 and its length is 68 m. Find
(1) its breadth
(ii) the distance covered by a man in going 5 times around the field.​

Answers

Answered by melwinjo
11

Answer:

i) 50 m

ii)1180 m

Step-by-step explanation:

i) AREA OF A RECTANGULAR FIELD =L*B

                   3400=68*B

                  B=3400/68=50 m

                THEREFORE BREADTH IS 50 m

ii) PERIMETER OF THE RECTANGLE= 2(L+B)

                                                               2(68+50)

IF A MAN GOES AROUND THE RECTANGLE 5 TIMES =5*2*(68+50)

                                                                                   =1180 m

Answered by Rose08
25

Answer:-

The breadth of the rectangular field is 50 m.

The distance covered by a man in going 5 rounds is 1180 m.

Explanation:-

Given :

Area of rectangular field= 3400 m²

Length of rectangular field= 68 m

To find :

Breadth of the field

Distance covered by man in going 5 times around the field.

Solution :

Area= 3400 m²

We know that the formula of area of rectangle is (Length×Breadth) sq.unit

 =  > l \times b = 3400 \: {m}^{2}

 =  > 68 \: m \:  \times b = 3400 \: {m}^{2}

 =  > b =  \dfrac{3400 \:  {m}^{2} }{68 \: m}

 =  > b = 50 \: m

Hence, The breadth of the field is 50 m.

Now,

We know that the formula of perimeter of rectangle is= 2(length+breadth) unit

 =  > perimeter = 2(68 + 50) \: m

 =  > perimeter = 2 \times 118 \: m

 =  > perimeter = 236 \: m

Hence, The perimeter of the field is 236 m.

Therefore, The distance covered by a man in going 5 rounds=> (5×236)m= 1180 m

Similar questions