Question

7. The area of four walls of a room is 180 m. If the sum of its length and breadth is 10 m, find
the height.​

Answer 1

Answer:

CSA= 2(l+b)h

180= 2×10×h

180=20h

180/20 =h

h=9m

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Answer 2

Answer :-

• The height of the room is 9m.

Step-by-step explanation:

To Find :-

• The height of the room

Solution:

Given that,

• Sum of length and breadth of room = 10m
• Area of four walls of room = 180m

Assumption: Let us assume the height of the room as "h"

As we know that,

Area of four walls = [2(l+b) × h] sq. units,

Where,

• l = Length
• b = Breadth
• h = Height

According the question,

=> [ 2 ( l + b ) × h ] = 180

=> [ 2 ( 10 ) × h ] = 180

=> 2 × 10 × h = 180

=> 20 × h = 180

=> h = 180/20

=> h = 18/2

=> h = 9

Hence,

• The height of the room is 9m.

Additional information :-

Some more information related to cuboid :-

• Total surface area = 2 ( lb + bh + hl ) sq. units
• Lateral surface area = 2 [ ( l + b ) × h ] sq. units
• Area of four walls = [ 2 ( l + b ) × h ] sq. units
• Volume = ( l × b × h ) cubic units.