7. The areas of two similar triangles are in the ratio 25: 100. If one of the corresponding
sides is 8cm, then the length of the other side is,
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let two similar triangle be ABC and triangle DEF and one of the corresponding be L(AB)= 8cm
ABC SIMILAR DEF
area(ABC)/area( DEF )= L(AB)/L(DE)
25/100=8/L(DE)
4×8=L(DE)
THEREFORE LINE DE IS 32CM
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