Question

7. The base of a triangle is 4cm longer than its altitude. If the area of the triangle is 48 sq.cm
then find its base and altitude.​

Answer 1

Answer:

base= 12 cm and altitude=8cm

Step-by-step explanation:

Base of a triangle is 4 cm longer than its altitude.

Area of triangle =48 cm

2

Let base of triangle =b

Altitude =b−4

Area =

2

1

×b×h=48

2

1

×b×(b−4)=48

b

2

−4b−96=0

(b−12)(b+8)=0

But, base cannot be negative

So, base =12 cm

Altitude=12−4=8 cm.