Question

7.) The coordinates of the centre if the ends of
the diameter are (2,-5) and (-2,9) ( )
A)(0.0) B) (2,-2) C) (-5,9) D)(0,2)​

Answer 1

Answer:

here both points are equidistant from center

Step-by-step explanation:

so take A(2,-5) ,B(-2,9) and center-O(x,y)

solve

AO=BO

take section formula

m:n=1:1(as bisects)

take

O(x, y)={2-2/2,-5+9/2}

=(0,2)

is the required center.

I hope it helps you

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Answer 2

FINAL ANSWER:-

D)(0,2)​

GIVEN:-

The coordinates of the center if the ends of  the diameter are (2,-5) and (-2,9)

FORMULA USED:-

mid points = $\frac{x1+x2}{2};\frac{y1+y2}{2}$

SOLUTION:-

the coordinates of 2 end points of lines are (2,-5) and (-2,9)

∴ $x1=2 ; x2=-2$

∴ $y1=-5 ; y2=9$

so,

coordinates of the center =  $\frac{x1+x2}{2};\frac{y1+y2}{2}$

$=\frac{2+(-2)}{2};\frac{(-5+9)}{2}\\=\frac{0}{2};\frac{4}{2}\\=0,2$

coordinates of the centre if the ends of  the diameter are (0,2)

HOPE THIS HELPS...