Question

7

The cubical body has dimensions 5 cm x 4 cm x 10 cm.  Its density is 5 g/ cm3 . Its mass will be​

Answer 1

Answer:

1 kg

Explanation:

As per the provided information in the given question, we have :

• Dimensions of cuboidal box = 5 cm x 4 cm x 10 cm
• Density = 5 g/cm³

We've been asked to calculate the mass.

Basically, here we need to apply any formula which will act as a linear equation. As we know that,

$\bigstar \quad\underline{\boxed { \pmb{\frak{Density}} = \dfrac{\pmb{\frak{Mass}}}{\pmb{\frak{Volume}}} }}$

Here, we need to calculate the volume of the cuboidal box first in order to find the mass of it. We've been provided with the dimensions of the box, so by using the formula of volume (V) of cuboidal box ;

$\longrightarrow \sf{\quad { V = \ell \times b \times h}}$

• V denotes volume
• l denotes length
• b denotes base
• h denotes height

$\longrightarrow \sf{\quad { V = \Big ( 5 \times 4 \times 10 \Big ) \; cm^3}}$

$\longrightarrow \sf{\quad { V = \Big ( 20 \times 10 \Big ) \; cm^3}}$

$\longrightarrow \quad \boxed{\sf { V = 200 \; cm^3}}$

Now, substitute the value of V from in the formula of Density within the value of density.

$\bigstar \quad\underline{\boxed { \pmb{\frak{Density}} = \dfrac{\pmb{\frak{Mass}}}{\pmb{\frak{Volume}}} }}$

Substitute the values.

$\longrightarrow \sf{\quad {5 \;g \: cm^{-3} = \dfrac{Mass}{200 \; cm^3} }}$

$\longrightarrow \sf{\quad {5 \;g \: cm^{-3} \times 200 \; cm^3 = Mass }}$

$\longrightarrow \sf{\quad {1000 \;g = Mass }}$

$\longrightarrow \quad \underline{\boxed{\pmb{\frak{1 \; kg = Mass}} }}$

Therefore, mass of the cuboidal box is 1 kg.

Answer 2

Answer: m = 1 kg.

Explanation:

m = ρV

=> m = (5 g/cm^3)(5 × 4 × 10 cm^3)

[Volume of cuboid = lbh cubic units]

=> m = 1000 g or 1 kg.