Question

7. The dimensions of the floor of a rectangular hall are 4 mx 3 m. The floor of the hall is to be tiled fully with
8 cm x 6 cm rectangular tiles without breaking tiles to smaller size. Find the number of tiles required.
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Answer 1

Step-by-step explanation:

area of floor = 4m x 3m

= 12m²

= 120,000cm²

now,

area of 1 tile = 8cm x 6cm

= 48cm²

now required tiles

= 120,000/48

=2,500 tiles

Answer 2

$\tt ฏGIVEN:-$

$\tt length \: of \: floor = 4m = 400cm$

$\tt breadth\: of \: floor= 3m = 300cm$

$\tt length\: of \: single \: tile= 8cm$

$\tt breadth\: of \: single \: tile= 6cm$

$\tt ฏFIND:-$

$\tt no. \: of \: tiles \: reqire = ?$

$\tt ฏSOLUTION:-$

$\tt area \: of \: floor = 400 \times 30 \\ \tt = 120000 {cm}^{2}$

$\tt area \: of \: each \: tile= 8 \times 6 = 4 {cm}^{2}$

$\tt now \: let \: no. \: of \: tiles = x$

$\tt = > area \: of \:hall= x\times area \: of \: each \: tile$

$\tt = > 120000 = x(48)$

$\tt = > x = \frac{ \cancel{ 120000}}{ \cancel{48}} = 2500$

$\boxed{ \tt so \: total \: no. \: of \: tile \: is \boxed{2500}}$