Question

7. The distance of the point P(-6, 8) from the origin is please answer this fast
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Answer 1

Step-by-step explanation:

the distance of the point P(6,-8) from the origin (0,0) is 10 units.

Answer 2

$\large\bf{\orange{Answér \:↝}}$

The distance p of a point P(x,y) from the origine is $P( {x}^{2} + {y}^{2} )$

Here P(x,y) = (-6,8).

∴ $P = \sqrt{{x}^{2} + {y}^{2} }$

$= \sqrt{( { - 6)}^{2} + {(8)}^{2} }$

$= \sqrt{36 + 64}$

$= \sqrt{100}$

= 10 units

The distance of the point P(-6, 8) from the origin is 10 units