Question

7 The equilibrium constant for the reaction
Cu (s) + 2Ag+ (aq) + Cu²+ (aq) + 2Ag (5)
is 2.0 x 10'5 at 298 K. Find the equilibrium
concentration of Cu²+ (aq) if that of Ag+ (aq) is
1.0 x 10-11 mol L .​

Answer 1

Answer:

Explanation:

equilibrium=product of concentrations of products/product of concentrations of reactants

substitute the values we have

2.0 x 10'5=cu++*107.8^2/63.5*(10^-11)^2