Question

7. The equivalent resistance between points 1 and 2
of the circuit shown .​

Answer 1

Answer :

We have asked to find equivalent resistance between 1 and 2$.$

★ Equivalent resistance of series connection is given by

• R = R₁ + R₂ + ... + Rₙ

★ Equivalent resistance of parallel connection is given by

• 1/R = 1/R₁ + 1/R₂ + ... + 1/Rₙ

Now see the left part of circuit. Three resistors of resistances 1Ω, 1Ω and 2Ω are connected in series.

➝ R₁ = 1 + 1 + 2

➝ R₁ = 4Ω

After solving this, 4Ω and 4Ω come into parallel.

➝ R₂ = (4 × 4) / (4 + 4)

➝ R₂ = 16/8

➝ R₂ = 2Ω

Finally three resistors of resistances 1Ω, 2Ω and 2Ω come into series.

➝ Req = 1 + 2 + 2

➝ Req = 5Ω

[Refer to the attachment for better understanding]