Question

7. The figure , AB is diameter of circle
ARQ and RBQ are straight lines. find
angle BPR​

Answer 1

Exterior angle of ∆ is equal to the sum of pair in interior opposite angles

angle ABP = 90° - angle BAP

===========> 90° - 35° = 55°

angle APR = angle ABR = 60°

( Angles subtended by the same chord on the circle are equal )

angle BPR = 90° - angle APR = 90° - 60° = 30°