Question

*7. The figure shows a circle and two identical semicircles in a square. Find
the total area of the shaded parts. (Take Ti = 3.14)
16 cm​

Answer 1

Answer:

Area of shaded region = area of ∆ABC - area of ∆ADB.

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∆ADB is a right angle triangle.

In ∆ADB,

AD = 12 cm

BD = 16 cm

Ar(∆ADB) = 1/2 × base × height

=> Ar(∆ADB) = 1/2 × AD × BD

=> Ar(∆ADB) = 1/2 × 12 × 16

=> Ar(∆ADB) = 96 cm^2

____________________

you can find AB by using Pythagoras theorem.

The sides of the triangle are 48cm, 52cm and 20cm.

_______________________

Area of shaded region = area of ∆ABC - area of ∆ADB.

=> Area of shaded region = 480 - 96

=> Area of shaded region = 384 cm^2

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