Question

7. The figure shows a trapezium ABCD where
AB is perpendicular to AD, AB = 12 cm, BC = 14 cm
and AD= 10 cm. Find the area of the shaded regions,
12 cm
A
B
10 cm
E
A 14 cm
D​

Answer 1

Step-by-step explanation:

Answer

Given: trapezium ABCD, ∠DAB=90

∘

, AD=10, BC=4 cm ,Area=24.5 sq.cm

Area of trapezium =

2

1

(Sum of parallel sides) (Perpendicular)

24.5=

2

1

×(10+4)×AB

AB=3.5

Area of quadrant ABE=

360

θ

π(AB)

2

Area of quadrant ABE=

360

90

×

7

22

(3.5)

2

Area of quadrant ABE= 9.625cm

2

Area of shaded portion = Area of trapezium − Area of quadrant ABE

Area of shaded portion = 24.5−9.625

Area of shaded portion = 14.375 cm

2

=14 cm

2

(rounding off to the nearest integer)

Answer 2

Answer:

Area of shaded part = 144 cm square

Area of unshaded part = 84 cm square

so Area of shaded regions = 60 cm sqaure