Question

7
The following data are needed for this question.

∆H; (P4010(s)) = -3012kJ mol
∆H; (H2O(l)) = -286 kJ mol
∆H; (H3PO4(s)) = -1279 kJ mol

What is ∆H® for the reaction shown?

P4O10(s) + 6H2O(l) → 4H3PO4(s)

A-9844 kJ mol-¹
B -388 kJ mol-¹
C -97 kJ mol-¹
D +2019 kJ mol-¹​

Answer 1

Answer:

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