Question

7. The force between two equal charges placed in a medium
at a distance of 9 cm from each other is 16 dyne. On
increasing one of the charges by 56 statC, it is found that the
distance between the charges must be changed by 3 cm in
order to keep the force between them the same. Calculate
the magnitude of the charges and the dielectric constant of
the medium. Given, 1 C = 3 × 109 statC.
[Ans. 72 statC ;4]​

Answer 1

Answer:

k , q1 and q2 .

Explanation:

Dear Student ,

Here in this case use the equation ,

F=kq1q2r2When distance is r=9 cm then , 16=kq1q281 . (1)when r=(9+3)=12 cm then ,16=kq1(q2+56)144.(2)Now solving this two equations you will get , k , q1 and q2 .F=kq1q2r2When distance is r=9 cm then , 16=kq1q281 .(1)when r=(9+3)=12 cm then ,16=kq1q2+56144 .(2)Now solving this two equations you will get , k , q1 and q2 .

Regards , mark brainliest plz!