Question

7. The heights of A ABC and ADBC are 4
cm and 6 cm respectively. The
ratio of areas of A ABC and ADBC is​

Answer 1

Step-by-step explanation:

GIVEN HIGHT OF TRIANGLE ABC = 4CM

AND HIGHT OF TRIANGLE DBC = 6 CM

NOW THE AREA OF TRIANGLE

NOW THE AREA OF TRIANGLE ABC ( BASE = BC AND HEIGHT = 4CM )

=

AREA =

NOW AREA OF ABC UPON AREA OF DBC

WE HAVE

2 : 3

Answer 2

answer,, 2:3

Step-by-step explanation:

height of the triangle abc and dbc are 4 and 6

area = 1/2base ×height

area of triangle abc is =1/2×base × height

base are same =bc in both triangle

abc=1/2×bc×4=2bc

area of triangle abc =2bc

now area of triangle dbc=1/2×bc×6=3bc

area of triangle abc/dbc,, =ratio

2 bc, /3 bc

ratio =2:3