Question

7. The inductance of a coil is 1.0 H. Calculate its inductive
reactance for AC of frequency 50 Hz. Ans. 314 22.
1.atiste

Answer 1

Given: The inductance of a coil is 1 H. The frequency of AC current is 50 Hz

To find: Inductive reactance of the coil

Explanation: Let the inductance of coil be denoted as L. Therefore, L= 1 H

The frequency given is 50 Hz. Let angular frequency be denoted as ω. The formula relating angular frequency with frequency is:

ω= 2πf where f is frequency

=> ω= 2*3.14*50

= 314 rad/s

The formula for calculating inductive reactance is: Inductive reactance= Lω

= 1 * 314 Ω

= 314 Ω

The unit for inductive reactance is same as that of resistance of the circuit.

Therefore, the value for inductive reactance in the circuit is 314 Ω.

Answer 2

Given:

The inductance of a coil ($L$) = $1.0$ H

Frequency ($f$) = $50$ Hz

To find:

The inductive reactance of AC $X_{L}$

Formula used:

$X_{L}$ = ω $L$

SInce, ω = $2\pi f$

$X_{L}$ = $2\pi fL$

Step-by-step explanation:

$X_{L}$ = $2$ × $3.14$ × $50$ × 1

$X_{L}$ = $314$

Answer:

Therefore, the inductive reactance of AC of frequency $50$ Hz is $314$