Question

7. The inner circumference of a circular track is 242 m. The track is uniformly 7 m wide. Find area of the track .​

Answer 1

Answer:
1848m²

Step-by-step explanation:

2πr = 242m

==> 2 × 22/7 × r = 242m

==> 44/7 × r = 242m

==> r = 242/1 × 7/44

==> r = 5.5 × 7

==> r = 38.5m

VERIFICATION:-

the inner circumference of the track = 2πr

= 2 × 22/7 × 38.5

= 1694/7

= 242m

hence verified

thus the radius of the inner circumference of the track is 38.5m.

GIVEN, that the track is 7m wide.

therefore the radius along with the track = 38.5 + 7

= 45.5m

the area along with the track = πr²

= 22/7 × 45.5 × 45.5

= 45545.5/7

= 6506.5m²

area without track = πr²

= 22/7 × 38.5 × 38.5

= 32609.5/7

= 4658.5m²

therefore area of the track = 6506.5 - 4558.5

= 1848m²