Question

7. The largest number which divides 615 and 963 leaving remainder 6 in each case is

(a) 82 (b) 95 (c) 87 (d) 93

Kindly solve it




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Answer 1

Answer:

Correct option is (c)

i.e. 87

Answer 2

Explanation:

we have to find the largest number which divide 615 and 963 leaving remainder 6 in each case.

so let us subtract 6 from 615 and 963

⇒ 615−6=609

⇒ 963−6=957

now lets find the HCF

⇒ prime factorisation of 609=29×3×3

prime factorisation of 957=29×3×11

now lets take out the common factors from both the cases

⇒ 29 and 3

x=29×3=87