7.
The LCM and HCF of two numbers are 196 and 20 respectively. How many
such pair(s) of numbers is possible?
(A) 0
(B) 1
(C) 2
(D) 3
(E) None of these
Please tell me answer with step by step explain.
I mark first answer brainliest.
Answers
Answered by
3
Answer:
none
as hcf is highest common factor
therefore, a number x should always be a multiple of its hcf.
similarly, lcm is lowest common multiple
therefore, a number should always be a factor of its lcm
therefore, lcm of a number is a multiple of its hcf
but, we can observe that :
196 is not a multiple of 20
therefore, no pair of number are possible in this case.
Please Mark as BRAINLIEST ❤️❤️❤️
binodinib882:
Tell me step by step explain
ok.
wait 2 min I am editing
Ok bro
oh sorry non
none of them....
Answer book me 2 pair diya gaya hai . Sorry, it's wrong. So i can't brainliest you .
But yar Mene be pahale book me check kiya tha.... it was 2... so I give the answer as 2. But the real answer is non....
there is some error in book's answer
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