7. The length of a rectangle is one and half
times its breadth. If the perimeter of the
rectangle is 100 cm, find the length and the
breadth of the rectangle.
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let the breadth be x and length be 3/2 x
perimeter = 100 CM
perimeter = 2(l+b)
100=2(3/2x+x)
100=6/2x+2x
100=6/2x+4/2x
100=10/2x
100×2=10x
200=10x
200/10=x
20=x
breadth = 20 CM
length = 3/2×20
=30 CM
verification :-
perimeter = 2(l+b)
=2(30+20)
=2×50
=100 CM
perimeter = 100 CM
perimeter = 2(l+b)
100=2(3/2x+x)
100=6/2x+2x
100=6/2x+4/2x
100=10/2x
100×2=10x
200=10x
200/10=x
20=x
breadth = 20 CM
length = 3/2×20
=30 CM
verification :-
perimeter = 2(l+b)
=2(30+20)
=2×50
=100 CM
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