Question

7. The line passing through (-4, -2) and (2, -3)
is perpendicular to the line passing through
(a, 5) and (2, -1). Find a.
​

Answer 1

Step-by-step explanation:

A line passing through (−4,−2) & (2,−3).

Equation of line is

y+3=

−2−4

−2+3

(x−2)

y=

6

−x

+

3

1

−3 ……….(1)

Slope of line (1) =[m

1

=

6

−1

]

Equation of line passing through (a,5) & (2,−1)

y+1=

a−2

5+1

(x−2)

y=

a−2

6

x−

a−2

12

−1 ………(2)

Slope of line (2)=[m

2

=

a−2

6

]

Since line (1) & (2) are perpendicular then [m

1

m

2

=−1]

6

−1

×

a−2

6

=−1

a−2=1

[a=3]

Hence for [a=3] line (1) & (2) are perpendicular.