Physics, asked by pousephdevassy9588, 1 year ago

7. The mass of earth is 6x1024 kg and that of the moon is 7.4x 1022kg. If the distance between the earth and the moon is 3.84x105km. Calculate the force exerted by the earth and the moon. 2

Answers

Answered by kotninishita123
4

I think Soo

Hope it is right


Attachments:
Answered by shaktisrivastava1234
24

 \huge  \sf  {\fbox{\fbox{\red{\fbox{Answer:}}}}}

 \huge \bf{Given:-}

\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}

 \sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}

\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}

\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}

 \sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}

 \huge \bf{To \: find:- }

\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}

 \huge \bf{Formula \: used: - }

  \leadsto\sf{F =G \times  \frac{m_1 \times m_2}{r^2}  }

 \huge \bf{Concept \: used: - }

  \sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k  {g}^{ - 2}  }

  \huge\bf{According \: to \: Question:-}

\bf{F = \frac{6.7 \times  {10}^{ - 11}  \times 6 \times  {10}^{24}  \times 7.4 \times  {10}^{22}} {(3.84 \times  {10}^{8} )^{2} } = 2.01 \times  {10}^{20} newtons}

 \sf\longmapsto{2.01 \times  {10}^{20} newtons}

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